mybatis collection多层嵌套,在mybatis中,使用association标签来解决
目录
协会标签多层嵌套问题排查从代码上看没有什么问题正常代码如下联合集合嵌套这个返回集合有什么用呢
association标签多层嵌套问题
米巴提斯里查询使用嵌套联合标签时,发现内层的联合查询的结果一直为空
排查
检查结构化查询语言执行情况,发现有数据返回,排除检查财产的值是否和持久化类中的对应,值一致,排除检查圆柱的值是否和数据库的相对应,相对应,排除那么应该是框架没有把数据映射到位了,经过排查是联合中列前缀被不对应
结果映射id= base result map type= a . b . c . d . e id column= id property= id /result property= work time column= work _ time /result property= model column= model /result property= status column= status /association property= interfaceUpstream Java type= interfaceUpstream 列前缀= ui _ id column= id property= id /result property= interface name column= interface _ name /interface id,ii.model,ii.status,ii.work_time,ui.id AS ui_id,ui.interface_name AS ui_
interface_name, ui.interface_type AS ui_interface_type, ui.frequency AS ui_frequency, ui.address AS ui_address, ui.template_or_sql AS ui_template_or_sql, ui.status AS ui_status, sys.id AS sys_id, sys.system_name AS sys_system_name, sys.system_name_en AS sys_system_name_en, sys.belong AS sys_belong, sys.status AS sys_status, ser.id AS ser_id, ser.ftp_ip AS ser_ftp_ip, ser.ftp_port AS ser_ftp_port, ser.ftp_account AS ser_ftp_account, ser.ftp_password AS ser_ftp_password </sql>
从代码上看没有什么问题
原因是association在进行多层嵌套时,mybatis会将外层association的columnPrefix值与内层的进行并合,
如外层columnPrefix值位ui_, 内层为sys_, 那么在SQL中就不能这样 sys.id AS sys_id 了,需要将ui_前缀加上,变成 sys.id AS ui_sys_id ,这样mybatis在匹配的时候才会将数据映射到对应association上
正常代码如下
SELECT ii.Id, ii.model, ii.status, ii.work_time, ui.id AS ui_id, ui.interface_name AS ui_interface_name, ui.interface_type AS ui_interface_type, ui.frequency AS ui_frequency, ui.address AS ui_address, ui.template_or_sql AS ui_template_or_sql, ui.status AS ui_status, sys.id AS ui_sys_id, sys.system_name AS ui_sys_system_name, sys.system_name_en AS ui_sys_system_name_en, sys.belong AS ui_sys_belong, sys.status AS ui_sys_status, ser.id AS ui_ser_id, ser.ftp_ip AS ui_ser_ftp_ip, ser.ftp_port AS ui_ser_ftp_port, ser.ftp_account AS ui_ser_ftp_account, ser.ftp_password AS ui_ser_ftp_password
问题解决!
association集合嵌套
学了一下mybatis的查询返回值的集合嵌套,先查了查官网:
这个返回集合有什么用呢
举个例子三张表
hr_job_department
hr_job_position
第三张表里在表示部门和职位的时候只用了上面两张表的主键
但是查询的时候,希望表示下面这样的结果
所以返回值是不止一个对象,这样就用到了集合嵌套
<resultMap id="userInfoMap" type="com.advancedc.hrsys.entity.UserInfo"><id column="id" property="id" /><result column="name" property="name" /><result column="gender" property="gender" /><result column="id_card" property="idCard" /><result column="is_married" property="isMarried" /><result column="phone" property="phone" /><result column="priority" property="priority" /><result column="entry_time" property="entryTime" /><result column="full_time" property="fullTime" /><result column="created_time" property="createdTime" /><result column="edited_time" property="editedTime" /><association property="jobDepartment" column="id"javaType="com.advancedc.hrsys.entity.JobDepartment"><id column="jdid" property="id" /><result column="jdname" property="name" /></association><association property="jobPosition" column="id"javaType="com.advancedc.hrsys.entity.JobPosition"><id column="jpid" property="id" /><result column="jpname" property="name" /></association></resultMap>
只需要知道:
(1)column表示数据库字段
(2)property表示Java里的值
而且我这里的主键都是id所以会出现重名的情况,在SQL语句里,查询时就要赋予别名才能加以区分,返回结果resultMap就如上图所示
<select id="queryUserInfoBySomeone" resultMap="userInfoMap" resultType="com.advancedc.hrsys.entity.UserInfo">SELECTui.id,ui.name,ui.gender,ui.id_card,ui.is_married,ui.department_id,ui.position_id,ui.phone,ui.priority,ui.entry_time,ui.full_time,ui.created_time,ui.edited_time,jd.id jdid,jd.name jdname,jp.id jpid,jp.name jpnameFROMhr_user_info uiINNER JOINhr_job_department jdONui.department_id=jd.idINNER JOINhr_job_position jpONui.position_id=jp.id<where><if test="someone.id>0">and ui.id = #{someone.id}</if><if test="someone.gender!=null">and ui.gender = #{someone.gender}</if><if test="someone.name!=null">and ui.name = #{someone.name}</if><if test="someone.idCard!=null">and ui.id_card = #{someone.idCard}</if><if test="someone.isMarried!=null">and ui.is_married = #{someone.isMarried}</if><if test="someone.jobDepartment!=null and someone.jobDepartment.id!=null">and ui.department_id = #{someone.jobDepartment.id}</if><if test="someone.jobPosition!=null and someone.jobPosition.id!=null">and ui.position_id = #{someone.jonPosition.id}</if><if test="someone.phone!=null">and ui.phone = #{someone.phone}</if><if test="someone.entryTime!=null">and ui.entry_time = #{someone.entryTime}</if><if test="someone.fullTime!=null">and ui.full_time = #{someone.fullTime}</if></where></select>
上图用了INNER JOIN来查询看上去挺简洁的,有一种不简洁的写法如下,虽然也能得到结果,但是不知道性能对比如何
SELECTui.id,ui.name,ui.gender,ui.id_card,ui.is_married,ui.department_id,ui.position_id,ui.phone,ui.priority,ui.entry_time,ui.full_time,ui.created_time,ui.edited_time,(select id jdid from hr_job_department jd where jd.id=ui.department_id) jdid,(select name jdname from hr_job_department jd where jd.id=ui.department_id) jdname,(select id jpid from hr_job_position jp where jp.id=ui.position_id) jpid,(select name jpname from hr_job_position jp where jp.id=ui.position_id) jpnameFROMhr_user_info ui;
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